4.
A steel plate that weighs 200 N and has a u with the asphalt of 0.6. If the steel
plate is sliding along the asphalt (constant velocity), what is the force of friction present?
Given
Want
Equation and solve

Respuesta :

Answer:

120N

Explanation:

The question gives us Mg = 200 N and in this equation Mg is equal to the normal force. Kinetic friction is calculated by normal force * coefficient of kinetic friction. Therefore kinetic friction = 200N * 0.6 = 120N