Respuesta :
[tex]\sf\large \green{\underbrace{\red{Answer⋆}}}:[/tex]
(a) R2, R3 are parallel and series with R1
(b) R1, R2 and R3 are in parallel
Explanation:
[tex] \sf R_1 = 2 \: ohm\\ \sf R_2 = 3 \: ohm \\ \sf R_3 = 6 \: ohm[/tex]
(a)
[tex] \sf R_2 \: and \: R_3 \: are \: in \: parallel \\ \sf so \: let \: the \: total \: of \: R_2 \: and \: R_3 \: be \: R_a[/tex]
[tex] \sf \large \frac{1}{R_a} = \frac{1}{R_2} + \frac{1}{R_3} \: as \: they \: are \: in \: parallel[/tex]
[tex] \sf R_a = \frac{1}{3} + \frac{1}{6} \\ \\ \sf \frac{1}{R_a} = \frac{2 + 1}{6} \\ \\ \sf \frac{1}{R_a} = \frac{3}{6} \\ \\ \sf \frac{1}{R_a} = \frac{1}{2} \\ \\ \sf R_a = 2 \: ohm[/tex]
Ra and R1 is in series
And there total will be R
[tex] \sf R = R_a + R_1 \\ \\ \sf R = 2 + 2 \\ \\ \sf R = 4 \: ohm[/tex]
(b)
[tex] \sf R_1 R_2 \: and \:R_3 \: are \: in \: parallel \: so \: total \: be \: R[/tex]
[tex] \sf \frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \\ \\ \sf \frac{1}{R} = \frac{1}{2} + \frac{1}{3} + \frac{1}{ 6} \\ \\ \sf \frac{1}{R} = \frac{3+ 2 +1 }{6} \\ \\ \sf \frac{1}{R} = \frac{6}{6} \\ \\ \sf R = 1 \: ohm[/tex]
