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Hailey loves to hang out at the bowling alley!
With one pin still standing, she rolls a 6-kg
bowling ball down the lane hitting the pin head
on with a speed of 5 m/s. The 1.5-kg pin
acquires a forward velocity of 12 m/s. How fast
is the bowling ball travelling after the collision

Respuesta :

The velocity of the bowling ball travelling after the collision will be 6.4 m/sec. Apply law of conservation of momentum principle in given problem.

What is the law of conservation of linear momentum?

According to the law of conservation of linear momentum before the collision is equal to the momentum after the collision. These laws state that about how momentum gets conserved.

Apply law of conservation of momentum principle;

m₁v₁+m₂v₂=(m₁+m₂)V

6 kg×5 m/s+1.5 kg×12= 7.5 kg*V

48=7.5 kg*V

V=6.4 m/sec

Hence,the velocity of the bowling ball travelling after the collision will be 6.4 m/sec.

To learn more about the law of conservation of momentum; brainly.com/question/1113396#SPJ1

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