what are the zeros of the polynomial shown

Answer:
x = -13,13
Step-by-step explanation:
Set [tex]x^2[/tex]-169 equal to zero.
[tex]x^2[/tex]-169 = 0
[tex]x^2[/tex] = 169
x = ±13
The "±"sign means positive and/or negative so the answer is both positive and negative 13 or x = -13,13.
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