[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's get started ~
According to question :
[tex]\sf \dashrightarrow y \propto \dfrac{1}{x} [/tex]
[tex]\sf \dashrightarrow y = k\dfrac{1}{x} [/tex]
Now, we have been given that when y = 11, x = 8
Let's plug these values in equation to find value of k ~
[tex]\sf \dashrightarrow 11 = k \cdot\dfrac{1}{8} [/tex]
[tex]\sf \dashrightarrow k = 11 \times 8[/tex]
[tex]\sf \dashrightarrow k =88[/tex]
we got the value of proportionality constant. now we have been asked to find the value of y when x = 16
So, let's use the equation ~
[tex]\sf \dashrightarrow y = k \cdot\dfrac{1}{x} [/tex]
[tex]\sf \dashrightarrow y = 88\cdot\dfrac{1}{16} [/tex]
[tex]\sf \dashrightarrow y = \dfrac{11}{2} [/tex]
[tex]\sf \dashrightarrow y = 5.5[/tex]
I hope you understood the whole procedure ~
