The initial concentration in the reaction mixture will contain [A] = 0.1 M and [B] = 1.0 M
Below is the reaction
A(g) → B(g)
And the equilibium constant will be explained in terms of [A] and [B]:
Keq = 10 = [B]/[A]
If the first conditions are that [A] = 1.1 M and [B] = 0.0 M, the conditions at equilibrium is:
[A] = 1.1M - x
[B] = 0.0M + x
Now we rewrite Keq:
Keq = 10 = [0.0 +x] / [1.1 -x]
at the end we got it for x:
10 = [0.0 +x] / [1.1 -x]
10 * (1.1-x) = x
11 - 10x = x
11 = 11x
x = 1
equilibrium, the concentrations are:
[A] = 1.1 M - 1 = 0.1 M
[B] = 0.0 M + 1 = 1.0 M
Thus, the concentration of A is 0.1 M and the concentration of B is 1M.
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