Answer:
a₅ = 80 , [tex]a_{n}[/tex] = 5[tex](2)^{n-1}[/tex]
Step-by-step explanation:
to find a term in the geometric sequence multiply the previous term by r
a₁ = 5
a₂ = a₁ × 2 = 5 × 2 = 10
a₃ = a₂ × 2 = 10 × 2 = 20
a₄ = a₃ × 2 = 20 × 2 = 40
a₅ = a₄ × 2 = 40 × 2 = 80
the nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
here a₁ = 5 and r = 2 , then
[tex]a_{n}[/tex] = 5 [tex](2)^{n-1}[/tex]
