Bag A contains 6 red marbles and 4 green marbles. Bag B contains 9 black marbles and 3
orange marbles. Find the probability of selecting one green marble rom bag A and one black marble from bag B

A) 2/9
B) 1/3
C) 2/5
D) 3//10​

Respuesta :

The probability that the  selecting one green marble from bag A and one black marble from bag B  is 0.138.

According to the statement

we have to find that the probability that the  selecting one green marble from bag A and one black marble from bag B.

So, For this purpose, we know that the

Probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes.

From the given information:

The probability that the  selecting one green marble from bag A and one black marble from bag B = 1/4+1/9

The probability that the  selecting one green marble from bag A and one black marble from bag B =0.138.

So, The probability that the  selecting one green marble from bag A and one black marble from bag B  is 0.138.

Learn more about Probability here

https://brainly.com/question/25870256

#SPJ9