contestada

Hydrogen peroxide can act as either an oxidizing agent or a reducing agent. (b) When H₂O₂ is treated with aqueous KMnO₄ the purple color of MnO₄⁻ disappears and a gas forms. In which role is H₂O₂ acting? What is the oxygen-containing product formed?

Respuesta :

a) Hydrogen peroxide acts as both a reducing and an oxidizing agent.

When H₂O₂ serves as an oxidizing agent, the oxygen of hydrogen peroxide (that is present in -1 oxidation state) is reduced to H₂O (-2 oxidation state).

H₂O₂ + 2H+ + 2e → 2H₂O

When H₂O₂ (-1 oxidation state)serves as a reducing agent, the oxygen of H₂O₂ is oxidized to O₂ ( 0 oxidation state) and bubbles are noticed. As a reducing agent:

2 KMnO₄ + 5 H₂O₂ + 3 H₂SO₄ --> K₂SO₄ + 5O₂ + 2MnSO₄ + 8H₂O

or

2 MnO₄- + 5 H₂O₂ + 6H⁺ → 5O₂ + 2Mn₂- + 8H₂O

What is Hydrogen Peroxide?

  • Hydrogen peroxide is the simplest kind of peroxide available
  • It is a colourless liquid and is used in aqueous solution for safety reasons
  • Concentrated hydrogen peroxide is a very reactive oxygen species and is used as a propellant in rocketry
  • It is often referred to as water with one more oxygen atom. It is acidic in nature and PH is about 4.5.
  • It acts as a bleaching agent and is also used as a disinfectant.

Laboratory Methods of Preparation:

When barium peroxide is acidified and the excess water is removed by the process of evaporation under reduced pressure, we obtain hydrogen peroxide. The following reaction will clarify this:

Equation:

BaO₂.8H₂O(s) + H₂SO₄(aq) → BaSO₄(s) + H₂O₂(aq) + 8H₂O(l)

Now,

When H₂O₂ is treated with aqueous KI it forms:

H₂O₂ and KI undergo a redox reaction, with hydrogen peroxide acting as an oxidizing agent and KI as a reducing agent. In the process, iodine gas is released owing to oxidation of KI.

Equation :

H₂O₂+ 2KI + 2H⁺ → I₂+ 2H₂O + 2K⁺

Thus form the above conclusion we can say that, H₂O₂ acting  as an oxidizing agent.

Oxygen containing product formed is H₂O.

b) The chemical reaction when H₂O₂ is treated with aqueous KMnO₄ is:

Equation:

2KMnO₄+5H₂O₂+3H₂SO₄→5O₂+2MnSO₄+K₂SO₄+8H₂O

Now,

 When H₂O₂ changes into H₂O , it acts as oxidizing agent (changes from      -1 to -2).

    When H₂O₂ changes into O₂ , it acts as reducing agent (changes from -1 to 0).

Thus from the above conclusion we can say that , hydrogen peroxide can act as oxidizing as well as reducing agent in the given reaction.

Learn more about Hydrogen peroxide here:brainly.com/question/4023822

#SPJ4

Disclaimer: The question given was incomplete on portal, Here is the complete question.

Question: Hydrogen peroxide can act as either an oxidizing agent or a reducing agent.

(a) When H₂O₂ is treated with aqueous KI, I₂ forms. In which role is H₂O₂ acting? What oxygen-containing product is formed?

(b) When H₂O₂ is treated with aqueous KMnO₄ the purple color of MnO₄⁻ disappears and a gas forms. In which role is H₂O₂ acting? What is the oxygen-containing product formed?