The displacement of the rocket is 699.5 m
Now e know that the term acceleration is the change of velocity with time. We have to obtain the acceleration of the object before we can be able to obtain the distance that have been traveled by the rocket.
Using
v = u + at
v = final velocity
u = initial velocity
a = acceleration
t = time
Then;
94.19 = 45.68 + 10.01a
94.19 - 45.68 = 10.01a
a = 94.19 - 45.68 / 10.01
a = 4.85 m/s^2
Thus;
v^2 = u^2 + 2as
s = v^2 - u^2/2a
s = ( 94.19)^2 - (45.68 )^2/2 * 4.85
s = 6785.1/9.7
s = 699.5 m
Thus, the displacement of the rocket is 699.5 m
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