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An automobile passes a point pp at a speed of 77 mph. at pp it begins to decelerate at a rate proportional to time. if after 5.0 sec the car has slowed to 53 mph, what distance has it traveled in ft?

Respuesta :

Answer:

373 ft

Explanation:

vf = vo  + (a) t        

 a is proportional to time = at   ( I assume DIRECTLY proportional to time)

   = vo  +  (at)t

53 = 77 + at^2

-24  = a ( 25)

a = - .96

df = do + vo t  + 1/2 a t^2    

  = 0   +  77(5)  + 1/2 ( -.96) (25) = 373 ft    

 ( I am not POSITIVE of this answer)

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