Respuesta :

The perimeter of an isosceles triangle is given by:

[tex]P\text{ = 2a + b}[/tex]

From the question, b = 2x; a = x^2 + 20

[tex]P\text{ = 2a }+b=2(x^2+20)+2x=2x^2+40\text{ + 2x}[/tex][tex]P=2x^2\text{ + 2x + 40}[/tex]

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