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a lake is stuck with 1,550 young carp. the number of the original fish alive after t years is given by the function P (t)= 1550e^-0.4t, when will there be 440 of the original fish left from to the nearest tenth

Respuesta :

[tex]\begin{gathered} 440=1550e^{-0.4t}\rightarrow \\ e^{-0.4t}=\frac{440}{1550} \\ -0.4t=\ln (\frac{44}{155})\approx-1.26 \\ t=\frac{1.26}{0.4}\approx3.14\approx3.1 \end{gathered}[/tex]

so the time needed is 3.1 years

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