The two angles shown are supplementary.162°Which equation can be solved to find the value of x, and what is the value of x?A.162° + Xo = 90°; x = 72B.162° + x° = 180°; x = 18C.162° + x = 360°; x= 198D.162° + x = 180°; x = 242

The two angles shown are supplementary162Which equation can be solved to find the value of x and what is the value of xA162 Xo 90 x 72B162 x 180 x 18C162 x 360 class=