We have to find the length of AR.
It will be the same as the length of AS, as they are both radius of the circle:
[tex]AR=AS[/tex]
AS is the hypotenuse of a right triangle with legs AT and TS.
Also, TS has half the length of SQ, so we have:
[tex]TS=\frac{1}{2}SQ=\frac{1}{2}\cdot12=6[/tex]
We then can calculate AS as:
[tex]\begin{gathered} AS^2=TS^2+AT^2 \\ AS^2=6^2+8^2 \\ AS^2=36+64 \\ AS^2=100 \\ AS=\sqrt[]{100} \\ AS=10 \\ \Rightarrow AR=10 \end{gathered}[/tex]
Answer: AR = 10
