which system of linear equations has a solution of (-2,1)?

Explanation
the easiest way to solve this is by checking the pair orderer on each system of equations and see it the equation becomes true, so
Step 1
check the solution on each system
a)
[tex]\begin{gathered} 2x+3y=-1 \\ x-y=-3 \end{gathered}[/tex]let
[tex]\begin{gathered} (x,y)\Rightarrow(-2,1) \\ x=-2 \\ y=1 \end{gathered}[/tex]replace
[tex]\begin{gathered} 2x+3y=-1 \\ 2(-2)+3(1)=-1 \\ -4+3=-1 \\ -1=-1\Rightarrow true \end{gathered}[/tex]and
[tex]\begin{gathered} x-y=-3 \\ -2-(1)=-3 \\ -3=-3\Rightarrow true \end{gathered}[/tex]so, A is the solution
Step 2
b)
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