Given:
The interior angles of a quadrilateral PQRS are 6x, 5x, 4x and 3x.
The objective is to find the value of x.
Explanation:
It is known that the sum of angles of a quadrilateral is 360°.
[tex]\angle P+\angle Q+\angle R+\angle S=360\degree[/tex]
To find x :
Now, sustitute the values of each angle in the above equation,
[tex]\begin{gathered} 6x+5x+4x+3x=360 \\ 18x=360 \\ x=\frac{360}{18} \\ x=20 \end{gathered}[/tex]
Hence, the value of x is 20.
