The magnitude of the force exerted by the girl on the woman is 100 N .
Given,
m₁ = 80 Kg
m₂ = 30 Kg
F1 = 100 N
F₂ = ?
By applying Newton's third law of motion, the force exerted by the girl is equal in magnitude to the force exerted by the boy but in opposite direction.
F₁ = F₂
F₁ = m₁ × a₁
F₂ = m₂ × a₂
∴ 100 = 80 × a₁
∴ a₁ = 100 / 80
∴ a₁ = 1.25 m/s
we know,
m₁ × a₁ = m₂ × a₂
∴ 80 × 1.25 = 30 × a₂
∴ 100 = 30 × a₂
∴ a₂ = 100 / 30
∴ a₂ = 3.33 m/s
Therefore,
F₂ = m₂ × a₂
∴ F₂ = 30 × 3.33
∴ F₂ = 100 N
Hence, the magnitude of the force exerted by the girl on the woman is 100 N .
Can learn more about the magnitude of force from https://brainly.com/question/20719505
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