Respuesta :

jsff42
First, since both of the equations are equal to y you can set the equations equal to each other. 
y=-2x +1 
y=-2x^2 + 3x +1 

-2x + 1= -2x^2 + 3x + 1 

Second, add 2x^2 and subtract 3x and 1 from both sides.
-2x + 1   = -2x^2 + 3x + 1 
-3x -1  +2x^2 +2x^2  -3x -1 
________________
2x^2 - 5x = 0 

Third, factor out an x. 
x(2x - 5) = 0 

Fourth, solve for x by setting each factor equal to 0. 

x= 0   2x-5=0 
               +5  +5
          _______
          2x = 5
         ----   ----
           2     2
         ________
          x=5/2 

So the values of x that satisfy the system of equations is 0 and 5/2.