Respuesta :
Answer with explanation:
Perimeter of watermelon field [tex]=71\frac{1}{3}[/tex] yard
1 yard =3 feet
So, perimeter
[tex]=71 \frac{1}{3}*3=\frac{214}{3}*3=214[/tex]feet
Width of Watermelon field = 44 feet
Kaisa , plants watermelon in the field in rows which are [tex]=2\frac{2}{3}=\frac{8}{3}[/tex] feet apart.
Number of watermelon planted in a single row =x
Let , Length of Watermelon field
[tex]=\frac{8(x-1){\text{feet}}}{3}[/tex]
Perimeter of field = 2 *[Length +Breadth]
[tex]214=2*[44+\frac{8(x-1)}{3}]\\\\\frac{214}{2}=44+\frac{8(x-1)}{3}\\\\107-44=\frac{8(x-1)}{3}\\\\63=\frac{8(x-1)}{3}\\\\x-1=\frac{3*63}{8}\\\\x=\frac{189}{8}+1\\\\x=\frac{197}{8}\\\\x=24\frac{5}{8}[/tex]
Number of watermelon in a row =24(approx)
Length of watermelon field
[tex]=\frac{8}{3}*\frac{197}{8}=65\frac{2}{3}[/tex] feet
Let number of rows of watermelon = y
[tex]\frac{197y}{8}=44\\\\ y=\frac{352}{197}=1.7860[/tex]
= 2 Rows(approximately)
