Respuesta :
I believe you use Boyles Law so P₁V₁=P₂V₂
so 125.0mmHg(x) = (145mmHg)(.4650L)
keep in mind this will give you an answer in L and you want mL
so 125.0mmHg(x) = (145mmHg)(.4650L)
keep in mind this will give you an answer in L and you want mL
Answer:
Initial volume of container = 0.5394 L (≅0.539 L)
Explanation:
Given:
Initial pressure of gas, P1 = 125.0 mmHg
Final pressure of gas, P2 = 145 mmHg
Final volume, V2 = 0.4650 L
To determine:
The initial volume V1 occupied by the gas
Explanation:
Based on the ideal gas equation
[tex]PV = nRT[/tex]
where P = pressure, V = volume ; n = moles of gas
R = gas constant, T = temperature
At constant n and T, the above equation becomes:
PV = constant
This is the Boyle's law
Therefore:
[tex]P1V1 = P2V2\\\\V1 = \frac{P2V2}{P1} = \frac{145 mmHg*0.4650L}{125mmHg} = 0.5394L[/tex]
