Respuesta :
Answer: The white precipitate formed is of lead carbonate having formula [tex]PbCO_3[/tex]
Explanation:
When lead iodide reacts with sodium carbonate, it leads to the formation of a white colored precipitate of lead carbonate along with sodium iodide.
This reaction is a type of double displacement reaction in which exchange of ions takes place.
The equation for the above reaction follows:
[tex]PbI_2(aq.)+Na_2CO_3(aq.)\rightarrow 2NaI(aq.)+PbCO_3(s)[/tex]
Hence, the white precipitate is of lead carbonate.
The white precipitate formed is most likely PbCO₃
Precipitate
From the question,
We are to determine the precipitate formed when PbI₂ is added to Na₂CO₃
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
PbI₂(s) + Na₂CO₃(aq) → PbCO₃(s) + 2NaI(aq)
From the above equation, the insoluble product formed is lead carbonate (PbCO₃).
Hence, the white precipitate formed is most likely PbCO₃.
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