Please help me.

A 60 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 200°C. How many moles of argon gas does the cylinder contain? (Given: R = 8.314 L∙kPa/K∙mol)

To simplify, we need to assume that the gas is an ideal gas so we can use the equation PV=nRT where P is pressure, V is volume, n is the number of moles, R is the universal gas constant and T is the temperature. We can calculate as follows:
PV = nRT
n = PV / RT
n = 10130(60) / 8.314 (200+273.15)
n = 154.51 mol argon gas

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Please help me. A 60 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 200°C. How many moles of argon gas does the cylinder contain? (Given: R = 8.314 L∙kPa/K∙mol)

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Please help me.

A 60 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 200°C. How many moles of argon gas does the cylinder contain? (Given: R = 8.314 L∙kPa/K∙mol)