Respuesta :
V₁/T₁ = V₂/T₂ = const
T₁=11+273=284K
V₂=3V₁
V₁/T₁=3V₁/T₂
T₂=3T₁
T₂=3*284=852K
t₂=852-273=579°C
T₁=11+273=284K
V₂=3V₁
V₁/T₁=3V₁/T₂
T₂=3T₁
T₂=3*284=852K
t₂=852-273=579°C
Answer:
At 579°C the volume of the gas be three times as big.
Explanation:
Under constant pressure:
Initial temperature of the gas =[tex]T_1=11^oC=284.15K[/tex]
Initial volume of the gas = [tex]V_1=V[/tex]
Initial temperature of the gas =[tex]T_2=?[/tex]
Initial volume of the gas = [tex]V_2=3V[/tex]
Applying Charles law:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex] (Constant pressure)
[tex]T_2=\frac{284.15 K\times 3V}{V}=852.45K=579 ^oC[/tex]
At 579°C the volume of the gas be three times as big.
