Respuesta :
The answer
according to the figure, we can solve this problem only by applying sines rule:
that is
sinA/a = sinB/b = sinC /c
As we observe, sin A /54 = sin B/27 = sin C/ c, and c = AB
besides, sinC > sinB > sinA , so the only answer possible is
27 < AB < 81
according to the figure, we can solve this problem only by applying sines rule:
that is
sinA/a = sinB/b = sinC /c
As we observe, sin A /54 = sin B/27 = sin C/ c, and c = AB
besides, sinC > sinB > sinA , so the only answer possible is
27 < AB < 81
we know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
So
see the attached figure to better understand the problem
1) [tex] AC+BC > AB [/tex]
[tex] 27+54 > AB\\ 81 > AB\\ AB < 81 [/tex]
2) [tex] 27+AB > 54 [/tex]
[tex] 27+AB > 54\\ AB > 54-27\\ AB > 27 [/tex]
3) [tex] 54+AB > 27 [/tex]
[tex] 54+AB > 27\\ AB > 27-54\\ AB > -27 [/tex]
therefore
the answer is the option
[tex] 27 < AB < 81 [/tex]
