Respuesta :
16<2(3x-1)<28 divide all terms by 2
8<3x-1<14 add 1 to all terms
9<3x<15 divide all terms by 3
3<x<5
x=(3,5) in interval notation
On a number line, it would be a line segment from 3 to 5 with open circles at 3 and 5.
On a coordinate system graph, it would be an infinitely high shaded plane between the vertical lines x=3 and x=5
8<3x-1<14 add 1 to all terms
9<3x<15 divide all terms by 3
3<x<5
x=(3,5) in interval notation
On a number line, it would be a line segment from 3 to 5 with open circles at 3 and 5.
On a coordinate system graph, it would be an infinitely high shaded plane between the vertical lines x=3 and x=5
From question ,
16<2(3x-1)=16<6x-2
=16+2<6x-2+2
=18<6x
=18/6<6x/6
=3<x
Again,
2(3x-1)<28
=6x-2<28
=6x-2+2<28+2
=6x<30
=6x/6<30/6
=x<5
So both of ther graphs 3<x and x<5 represents her solution
16<2(3x-1)=16<6x-2
=16+2<6x-2+2
=18<6x
=18/6<6x/6
=3<x
Again,
2(3x-1)<28
=6x-2<28
=6x-2+2<28+2
=6x<30
=6x/6<30/6
=x<5
So both of ther graphs 3<x and x<5 represents her solution
