Respuesta :
[tex] \frac{4x^2+36}{4x}* \frac{1}{5x} = \frac{4(x^2+9)}{20x^2} = \frac{x^2+9}{5x^2} [/tex]
Answer:
Step-by-step explanation:
The given equation is:
[tex]\frac{4x^2+36}{4x}{\times}\frac{1}{5x}[/tex]
On solving the above equation, we get
=[tex]\frac{4x^2+36}{(4x)(5x)}[/tex]
=[tex]\frac{4(x^2+9)}{(4x)(5x)}[/tex]
=[tex]\frac{x^2+9}{(x)(5x)}[/tex]
=[tex]\frac{x^2+9}{(5x^2)}[/tex]
which is the required simplified form.
Thus, the simplified form of the given equation [tex]\frac{4x^2+36}{4x}{\times}\frac{1}{5x}[/tex] is [tex]\frac{x^2+9}{(5x^2)}[/tex].