Respuesta :
W=ΔKE
F(d)=(1/2)mv^2
v=sqrt((2F(d)/m))
v=sqrt(2(80)(4)/10)
v=sqrt(640/10)
v=8
F(d)=(1/2)mv^2
v=sqrt((2F(d)/m))
v=sqrt(2(80)(4)/10)
v=sqrt(640/10)
v=8
Answer: The velocity of the object will be 8m/s.
Explanation:
Force exerted on the object = 80 N
Distance displaced by object by the action of force = 4 m
Mass of the object = 10 kg
Velocity gained by the object = v
Kinetic energy of the object = Work done on the object
[tex]\frac{1}{2}mv^2=Force\times displacement[/tex]
[tex]\frac{1}{2}\times 10\times v^2=80 N\times 4 m[/tex]
[tex]v^2=64 m^2/s^2[/tex]
[tex]v=8 m/s[/tex]
The velocity of the object will be 8m/s.
