Scores earned in individual tests will be calculated by the percentage of point value.
Sum of these scores should be equal to the score required for 90% of the total points.
The test score I need is 92%
From the table given in the picture,
Test - 1
Score in (test - 1) = 83% of 100
= [tex]\frac{83}{100}\times 100[/tex]
= 83
Test - 2
Score in (test - 2) = 91.6% of 250
= [tex]\frac{91.6}{100}\times 250[/tex]
= 229
Test - 3
Score in (test - 3) = 88% of 150
= [tex]\frac{88}{100}\times 150[/tex]
= 132
Test - 4
Let the score required in (test - 4) = [tex]x%[/tex]% of 300
= [tex]\frac{300x}{100}[/tex]
= 3x
Therefore, score earned in all tests = 90% of the total points (Points required in total)
83 + 229 + 132 + 3x = [tex]\frac{90}{100}\times (100+250+150+300)[/tex]
444 + 3x = 0.9(800)
444 + 3x = 720
3x = 276
x = 92
Therefore, in the last test score I need is 92%.
Learn more,
https://brainly.com/question/17111553
