Answer: Horizontal component of arrow :40.955 m/s
Vertical component of arrow :28.675 m/s
Explanation:
The initial speed of the arrow = u = 50 m/s
The horizontal component of the arrow =[tex]u_x=u\cos\theta [/tex]
The horizontal component of the arrow =[tex]u_y=u\sin\theta [/tex]
Angle between the velocity vector and x component = 35°
Horizontal component of arrow :
[tex]\cos\theta=\frac{u_x}{u}[/tex]
[tex]\cos35^o=0.8191=\frac{u_x}{50}[/tex]
[tex]u_x=0.8191\times 50=40.955 m/s[/tex]
Vertical component of arrow :
[tex]\sin\theta=\frac{u_y}{u}[/tex]
[tex]\sin35^o=0.5735=\frac{u_y}{50}[/tex]
[tex]u_y=0.5735\times 50=28.675 m/s[/tex]
Horizontal component of arrow :40.955 m/s
Vertical component of arrow :28.675 m/s
