Respuesta :
ANSWER
[tex]|A'B'| = 5 \: units[/tex]
EXPLANATION
The formula for calculating the scale factor is
[tex]k = \frac{image \: length}{object \: length} [/tex]
Or
[tex]k = \frac{ |A'B'| }{ |AB|} [/tex]
Where k is the scale factor.
We were given
[tex] |A'B'|=10[/tex]
This is the image length.
We substitute the scale factor and the image length in to the formula to get,
[tex] \frac{1}{2} = \frac{ |A'B'| }{ 10} [/tex]
Multiply both sides by 10 to get,
[tex] \frac{1}{2}\times 10= |A'B'|[/tex]
[tex]|A'B'| = 5 \: units[/tex]
[tex]|A'B'| = 5 \: units[/tex]
EXPLANATION
The formula for calculating the scale factor is
[tex]k = \frac{image \: length}{object \: length} [/tex]
Or
[tex]k = \frac{ |A'B'| }{ |AB|} [/tex]
Where k is the scale factor.
We were given
[tex] |A'B'|=10[/tex]
This is the image length.
We substitute the scale factor and the image length in to the formula to get,
[tex] \frac{1}{2} = \frac{ |A'B'| }{ 10} [/tex]
Multiply both sides by 10 to get,
[tex] \frac{1}{2}\times 10= |A'B'|[/tex]
[tex]|A'B'| = 5 \: units[/tex]
Answer:
Option (b) is correct.
The length of A'B' is 5 inches.
Step-by-step explanation:
Given : line segment AB is 10 inches long. AB is dilated to form A'B' with a scale factor of [tex]\frac{1}{2}[/tex]
we have to find the length of A'B'
Dilation of a figure is the increase or decrease in the length of the figure by a fixed scaling factor. if scaling factor is greater than 1 , then figure size increases, and if scaling factor is less than 1 , then figure size decreases.
Here, scaling factor is [tex]\frac{1}{2}[/tex] which less than 1 , so line segment A'B' decreases.
New image = scaling factor × original image
that is A'B' = [tex]\frac{1}{2}\times 10=5[/tex]
Thus, the length of A'B' is 5 inches.
Option (b) is correct.