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iGreen
Just create a problem and figure it out.

Let's say the original diameter is 4. This means the radius is 4/2 = 2.

A = 2πr^2

A = 2π(2)^2

A = 2π(4)

A = 8π

The new diameter is 50% larger than the original.
50% of 4 is 2. 2 + 4 = 6. So the new diameter is 6. The radius is 6/2 = 3.

A = 2πr^2

A = 2π(3)^2

A = 2π(9)

A = 18π

Old area was 8π, new area is 18π. Now divide the difference from the original area:

18π - 8π = 10π

10π/8π = 1.25 * 100 = 125%

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