Answer:
Maximum force of friction, F = 912.38 N
Explanation:
It is given that,
Mass of doghouse, m = 98 kg
Coefficient of friction between doghouse and the ground, μ = 0.95
We have to find the maximum force of friction between the doghouse and the ground. It is given by :
F = μ N
N = normal force = mg
F = μmg
F = 0.95 × 98 kg × 9.8 m/s²
F = 912.38 N
Hence, this is the required solution.
