Answer:
[tex]\sqrt{(0-y)^{2}+(0-1)^{2}}=2[/tex]
Step-by-step explanation:
we know that
In the circle of the figure the radius is equal to 2 units
The distance from the center of the circle (origin) to the point A must be same at the radius
so
Applying the formula's distance between two points
point A( 1,y) and point (0,0)
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
substitute the values
[tex]2=\sqrt{(0-y)^{2}+(0-1)^{2}}[/tex]
rewrite
[tex]\sqrt{(0-y)^{2}+(0-1)^{2}}=2[/tex]
