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About 2% of the population has a particular genetic mutation. 600 people are randomly selected. find the standard deviation for the number of people with the genetic mutation in such groups of 600. round answer to 4 decimal places.

Respuesta :

The standard deviation is 0.4801.

To find the standard deviation we use the formula:

s = √n(p)(1-p), where n is the sample size and p is the probability.

Using this, we have:
s = √600(0.02)(1-0.02) = √600(0.02)(0.98) = 0.4801.
MrRoyal

The standard deviation for the number of people with the genetic mutation in such groups of 600 is 3.4293

How to determine the standard deviation?

The given parameters are:

Proportion, p = 2%

Sample size, n = 600

The standard deviation is calculated as:

[tex]\sigma = \sqrt{np(1 - p)[/tex]

So, we have:

[tex]\sigma = \sqrt{600 * 2\% *(1 - 2\%)[/tex]

Evaluate

[tex]\sigma = 3.4293[/tex]

Hence, the standard deviation for the number of people with the genetic mutation in such groups of 600 is 3.4293

Read more about standard deviation at:

https://brainly.com/question/475676

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