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Calculate the mass of sodium acetate trihydrate required to make 100. ml of a 0.100 m solution. as part of your preparation for performing this experiment, record your answer to this question in your lab notebook so that you have it ready to use during the lab session. if you do not get this question correct, please make sure to revisit the calculation and check your corrected value with your ta prior to preparing the solution in lab.

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ChemistryHelper2024

Required moles of CH₃COONa.3H₂O = Molarity x Volume of solution in L

                                                            = 0.100 M x (100.0 mL)

                                                            = 0.100 M x 0.100 L

                                                            = 0.01 mol

Required mass of CH₃COONa.3H₂O = Required moles x Molar mass

                                                            = 0.01 mol x (136.08 g / mol)                                                                              = 1.3608 g

okpalawalter8

We have that the mass of CH₃COONa.3H₂O is mathematically given as

Ms=1.3608g

Chemical Reaction

Generally the equation for the  moles of CH₃COONa.3H₂O is mathematically given as

M= Molarity x Volume of solution in L

M =0.100 M x 100.0 mL

M=0.01mol

Hence

mass of CH₃COONa.3H₂O

Ms=0.01 mol x (136.08 g / mol)

Ms=1.3608g

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