Respuesta :
%(NaHCO3)= ((mass NaHCO3)/(mass NaHCO3 + mass water))*100%
m=Volume*Density
Density of water =1 g/ml
m(water) = Volume(water)*Density(water) = 600.0 ml * 1g/ml=600g water
%(NaHCO3)= ((20.0 g)/(20.0 g + 600 g))*100%=0.0323*100%=32.3%
m=Volume*Density
Density of water =1 g/ml
m(water) = Volume(water)*Density(water) = 600.0 ml * 1g/ml=600g water
%(NaHCO3)= ((20.0 g)/(20.0 g + 600 g))*100%=0.0323*100%=32.3%
32.3% is the percent by mass of [tex](NaHCO_3)[/tex] = in a solution containing 20.0 g of [tex](NaHCO_3)[/tex] dissolved in 600.0 ml of water.
What is a mass percentage?
The mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.
[tex]Percentage of (NaHCO_3)[/tex] = [tex]\frac{mass \;NaHCO_3 X 100} {mass \;NaHCO_3 + mass \;water}[/tex]
Mass of water =[tex]\frac{Volume \;of \;water}{Density \;of \;water}[/tex]
Density of water =1 g/ml
Mass of water = 600g
[tex]Percentage of (NaHCO_3)[/tex] = [tex]\frac{mass \;NaHCO_3 X 100} {mass \;NaHCO_3 + mass \;water}[/tex]
[tex]Percentage of (NaHCO_3)= \frac{20.0 g X 100} {20.0 g + 600 g}[/tex]
[tex]Percentage of (NaHCO_3)[/tex] = 32.3%
Hence, 32.3% is the percent by mass of [tex](NaHCO_3)[/tex] = in a solution containing 20.0 g of [tex](NaHCO_3)[/tex] dissolved in 600.0 ml of water.
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