Answer:
[tex]3.5022\times 10^{-15} m[/tex]is the radius of the sodium-22 nucleus.
Explanation:
[tex]r=r_o\times A^{\frac{1}{3}}[/tex]
Where:
[tex]r_o=1.25 \times 10^{-15} m[/tex] = Constant for all nuclei
r = Radius of the nucleus
A = Number of nucleons or atomic mass
Radius of the sodium-22 nucleus
Atomic mass of Na-22= 21.994434 u
A = 21.994434
[tex]r=1.25\times 10^{-15} m\times (21.994434)^{\frac{1}{3}} [/tex]
[tex]r=3.5022\times 10^{-15} m[/tex]
[tex]3.5022\times 10^{-15} m[/tex]is the radius of the sodium-22 nucleus.
