On a coordinate plane, rhombus D E F G is shown. It has points (1, 4), (4, 0), (1, negative 4), and (negative 2, 0).
The vertices of rhombus DEFG are D(1, 4), E(4, 0), F(1, –4), and G(–2, 0).

What is the perimeter of the rhombus?

units

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Answer:

20 units

Step-by-step explanation:

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The perimeter of the rhombus should be considered as the 20 units.

Calculation of the perimeter of the rhombus:

Since

firs we have to determine the DE

[tex]= \sqrt (4 - 1)^2 + ( 0 -4)^2\\\\= \sqrt ( 9 + 16)\\\\= \sqrt 25[/tex]

= 5

Here we know that

Perimeter = 4(side)

= 4(5)

= 20 units

Hence, The perimeter of the rhombus should be considered as the 20 units.

Learn more about rhombus here: https://brainly.com/question/18057835