The new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.
Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;
P₁V₁/T₁ = P₂V₂/T₂
Given the data in the question;
At standard remperature and pressure
To calculate the new volume of the helium gas, we subtsitute our given values into the expression above.
P₁V₁/T₁ = P₂V₂/T₂
P₁V₁T₂ = P₂V₂T₁
V₂ = P₁V₁T₂ / P₂T₁
V₂ = ( 1.0atm × 0.32L × 425.0K ) / ( 3.50atm × 273.15K )
V₂ = 136LatmK / 956.025atmK
V₂ = 0.14L
V₂ = 1.40×10²mL
Therefore, the new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.
Learn more about combined gas law here: brainly.com/question/25944795
