The titration of 25.0 ml of an iron(ii) solution required 18.0 ml of a 0.205 m solution of dichromate to reach the equivalence point. what is the molarity of the iron(ii) solution?

Respuesta :

The formula of this is : MV = MV or Molarity × Volume = Molarity × Volume. So you do:
25X = 18×.205=.1476M